Let Z be a standard normal random variable. Use the calculator provided, or this table, to determine the value of .
P (1.18 _< Z _< c) = 0.0854
Carry your intermediate computations to at least four decimal places. Round your answer to two decimal places.
Solution,
Using standard normal table,
P( 1.18 Z c) = 0.0854
= P( Z c) - P( Z 1.18) = 0.0854
= P( Z c) - 0.8810 = 0.0854
= P( Z c) = 0.8810 + 0.0854
= P( Z c) = 0.9664
= P( Z 1.83) = 0.9664
c = 1.83
P( 1.18 Z 1.83) = 0.0854
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