Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance.
DIVORCES:
MEAN 1587
MEDIAN 1340
STANDARD DEVIATION 1427.25
MINIMUM 98
MAXIMUM 6400
1. Clearly state a null and alternative hypothesis
2.Give the value of the test statistic
3. Report the P-Value
4. Clearly state your conclusion (Reject the Null or Fail to Reject the Null)
5.Explain what your conclusion means in context of the data.
SAMPLE SIZE 52
Given,
The hypothesis is,
since the sample size is greater than 30, we use z test statistic,
The corresponding p value is,
P = 0.00
Since, the p value is less than level of significance, we reject the null hypothesis.
We reject the null hypothesis that the average amount of divorces is greater than 4000 and we conclude that the average amount of divorces is less than or equal to 4000.
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