Let X = the number of defective fuses selected.
h(x; N, n, k) = [ kCx ] [ N-kCn-x ] / [ NCn ]
The probability at least one defective is:
Here N=12,k=5,n=3,x=1
P[X=1] = h(1;12,3,5)
=(5C1)*(7C2)/(12C3)
=5*21/220
=0.477273
The probability at least one defective is 0.477273.
7b). Which of these variables are discrete and which are continuous random variables?
a) The number of new professors in the school of Business and Economics Discrete
b) The time between buses from the airport to downtown. Continuous
c) The number of students registered in second year accounting Discrete
d) The volume of coffee consumed by the average student during the period. Continuous
e) The median age of international students in TRU. Discrete
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