The following data, which was provided from a sample of 158 Mass Mutual employees, shows how many phone calls they receive while they are at work.
Phone calls (per day): Frequency:
8-11 18
12-15 23
16-19 38
20-23 47
24-27 32
What is the standard deviation of the grouped data?
a. |
4.5 calls |
|
b. |
5.237 calls |
|
c. |
4.998 calls |
|
d. |
5.077 calls |
Solution:
Given that,
Class | Frequancy | Mid Value | d = x - A /h | f*d | f*d2 |
8 - 11 | 18 | 9.5 | -2 | -36 | 72 |
12 - 15 | 23 | 13.5 | -1 | -23 | 23 |
16 - 19 | 38 | 17.5 | 0 | 0 | 0 |
20 - 23 | 47 | 21.5 | 1 | 47 | 47 |
24 - 27 | 32 | 25.5 | 2 | 64 | 128 |
n = 158 | fd = 52 | fd2 = 270 |
Sample standard deviation is S
S = ( fd2 - (( fd )2 / n) n -1 ) *h
= ( 270 ) - (( 52 )2 / 158 ) 157*4
= (270 - 17.1139) /157*4
= 252.8861/ 157*4
= 6.107*4
= 1.2691*4
= 5.0766
Sample standard deviation is S = 5.077
Answer d. is correct.
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