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In the week before and the week after a? holiday, there were 10 comma 000 total?...

In the week before and the week after a? holiday, there were 10 comma 000 total? deaths, and 4921 of them occurred in the week before the holiday. a. Construct a 95?% confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday. b. Based on the? result, does there appear to be any indication that people can temporarily postpone their death to survive the? holiday?

Math   Statistics-And-Probability   
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Answer #1

For 95% confidence, z = 1.96

Sample proportion = 4921/10000 = 0.4921

Hence,

95% confidence interval will be:

(0.4823, 0.5019)

Since ths interval contains 0.5, this result do not suggest that people can temporarily postpone their death to survive the? holiday.

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