A roulette wheel has 38 slots in which the ball can land. Two of the slots are green, 18 are red and 18 are black. The ball is equally likely to land in any slot. The roulette wheel is going to be spun twice and the outcomes of the two spins are independent.
The probability that it never lands on green is
probability of not getting a green on single spin = 36/38 =
18/19 = 0.947368
This is a binomial distribution question with
n = 2
p = 0.947368
q = 1 - p = 0.0526
If we spin twice, probability of not getting any greeen on both spun = 0.8975 OPTION C
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