Question

You wish to test the following claim (Ha) at a significance level of α=0.005. Ho:p1=p2 Ha:p1≠p2 You obtain a sample from the first population with 174 successes and 70 failures. You obtain a sample from the second population with 434 successes and 197 failures. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion. There is not sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion. The sample data support the claim that the first population proportion is not equal to the second population proprtion. There is not sufficient sample evidence to support the claim that the first population proportion is not equal to the second population proprtion.

Answer 1

Now , the estimate of the sample proportions are ,

The pooled estimate is ,

The null and alternative hypothesis is ,

The test is two-tailed test.

The test statistic is ,

The p-value is ,

p-value= ; The excel function is , =2*(1-NORMDIST(1.159,0,1,TRUE))

Decision : Here , p-value >0.005

Theerfore , fail to reject Ho.

Conclusion : There is sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion.