Question

According to a recent​ study, the carapace length for adult males of a certain species of...

According to a recent​ study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of

mu equals 17.91μ=17.91

mm and a standard deviation of

sigma equals 1.53σ=1.53

mm. Complete parts​ (a) through​ (d) below.Click here to view page 1 of the standard normal distribution table.

LOADING...

Click here to view page 2 of the standard normal distribution table.

LOADING...

a. Find the percentage of the tarantulas that have a carapace length between

1616

mm and

1717

mm. The percentage of the tarantulas that have a carapace length between

1616

and

1717

is

nothing​%.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

b. Find the percentage of the tarantulas that have a carapace length exceeding

1919

mm.The percentage of the tarantulas that have a carapace length exceeding

1919

is

nothing​%.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

c. Determine and interpret the quartiles for the carapace length of these tarantulas.

The first quartile is

nothing.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

Interpret the first quartile. Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Type integers or decimals rounded to two decimal places as​ needed.)

A.This first quartile is

nothing​%

greater than the smallest carapace length.

B.This first quartile means that

nothing​%

of the carapace lengths are less than

nothing.

C.This first quartile means that

nothing​%

of the carapace lengths are equal to

nothing.

D.This first quartile is

nothing​%

less than the average carapace length.The second quartile is

nothing.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

Interpret the second quartile. Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Type integers or decimals rounded to two decimal places as​ needed.)

A.This second quartile means that

nothing​%

of the carapace lengths are equal to

nothing.

B.This second quartile is

nothing​%

less than the average carapace length.

C.This second quartile is

nothing​%

greater than the smallest carapace length.

D.This second quartile means that

nothing​%

of the carapace lengths are less than

nothing.

The third quartile is

nothing.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

Interpret the third quartile. Select the correct choice below and fill in the answer​ box(es) to complete your choice.

​(Type integers or decimals rounded to two decimal places as​ needed.)

A.This third quartile means that

nothing​%

of the carapace lengths are equal to

nothing.

B.This third quartile is

nothing​%

greater than the smallest carapace length.

C.This third quartile means that

nothing​%

of the carapace lengths are less than

nothing.

D.This third quartile is

nothing​%

less than the average carapace length.d. Obtain the

9595th

percentile for the carapace length of these tarantulas.The

9595th

percentile is

nothing.

​(Type an integer or decimal rounded to two decimal places as​ needed.)

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
According to a recent​ study, the carapace length for adult males of a certain species of...
According to a recent​ study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of μ=17.13 mm and a standard deviation of sigma equals 1.69 (σ=1.69)mm. Complete parts​ (a) through​ (d) below. a. Find the percentage of the tarantulas that have a carapace length between 15 mm and 16 mm. The percentage of the tarantulas that have a carapace length between 15 and 16 is ___%. ​(Type an integer or decimal...
According to a recent​ study, the carapace length for adult males of a certain species of...
According to a recent​ study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of  18.01 mm and a standard deviation of σ=1.69 mm. Complete parts​ (a) through​ (d) below. a) . Find the percentage of the tarantulas that have a carapace length between 16 mm and 17 mm. b) Find the percentage of the tarantulas that have a carapace length exceeding 19 mm. c) Determine and interpret the quartiles for the...
According to a recent​ study, the carapace length for adult males of a certain species of...
According to a recent​ study, the carapace length for adult males of a certain species of tarantula are normally distributed with a mean of mu equals 18.88 mm and a standard deviation of sigma equals 1.87 mm. Complete parts​ (a) through​ (d) below. .A) Find the percentage of the tarantulas that have a carapace length between 17 and 18 mm_____ % B). Find the percentage of the tarantulas that have a carapace length exceeding 20 mm. _____% C)Determine and interpret...
A study finds that the carapace length of an adult spider is normally distributed with a...
A study finds that the carapace length of an adult spider is normally distributed with a mean of 17.36 mm and a standard deviation of 1.5 mm. Let x denote carapace length for the adult spider. d. Find the​ z-scores that correspond to the percentage of adult spiders that have carapace lengths between 14 mm and 15 mm. The percentage of adult spiders that have carapace lengths between 14 mm and 15 mm is equal to the area under the...
According to a study conducted by an​ organization, the proportion of Americans who were afraid to...
According to a study conducted by an​ organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1 comma 1001,100 Americans results in 9999 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has decreaseddecreased. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A.This is not necessarily evidence...
A group of adult males has foot lengths with a mean of 26.68 cm and a...
A group of adult males has foot lengths with a mean of 26.68 cm and a standard deviation of 1.49cm. Use the range rule of thumb to identify the limits separating values that are significantly low or significantly high. Is the adult male foot length of 23.4 cm significantly low or significantly​ high? Explain. Significantly low values are ? cm or lower. ​(Type an integer or a decimal. Do not​ round.) Significantly high values are ? cm or higher. ​(Type...
The weight of an organ in adult males has a? bell-shaped distribution with a mean of...
The weight of an organ in adult males has a? bell-shaped distribution with a mean of 320 grams and a standard deviation of 45 grams. Use the empirical rule to determine the following. ?(a) About 99.7?% of organs will be between what? weights? ?(b) What percentage of organs weighs between 275 grams and 365 ?grams? ?(c) What percentage of organs weighs less than 275 grams or more than 365 ?grams? ?(d) What percentage of organs weighs between 185 grams and...
According to a study conducted by an​ organization, the proportion of Americans who were afraid to...
According to a study conducted by an​ organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A random sample of 1,300 Americans results in 143 indicating that they are afraid to fly. Explain why this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased. A. This is not necessarily evidence that the proportion of Americans who are afraid to fly has increased above 0.10 because the probability of...
A simple random sample from a population with a normal distribution of 100 body temperatures has...
A simple random sample from a population with a normal distribution of 100 body temperatures has x overbar =9 8.40°F ands = 0.62°F. Construct a 98​% confidence interval estimate of the standard deviation of body temperature of all healthy humans. Is it safe to conclude that the population standard deviation is less than 2.10°F​? ___°F < σ < ___°F ​(Round to two decimal places as​ needed.) Is it safe to conclude that the population standard deviation is less than 2.10°F​?...
The weight of an organ in adult males has a​ bell-shaped distribution with a mean of...
The weight of an organ in adult males has a​ bell-shaped distribution with a mean of 350 grams and a standard deviation of 15 grams. Use the empirical rule to determine the following. ​(a) About 68​% of organs will be between what​ weights?​ (b) What percentage of organs weighs between 320 grams and 380 grams? ​(c) What percentage of organs weighs less than 320 grams or more than 380 ​grams?​ (d) What percentage of organs weighs between 335 grams and...