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The Chamber of Commerce Miami Beach wishes to estimate the mean expenditures per tourist per visit...

  1. The Chamber of Commerce Miami Beach wishes to estimate the mean expenditures per tourist per visit to the city. A SRS of one hundred tourists was selected for investigation. From this sample, it was found that the mean expenditure was $800.00 per tourist per visit and standard deviation was $120.00 per tourist per visit. Construct a 95% confidence interval for the true mean expenditure per tourist.

Math   Statistics-And-Probability   
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Answer #1

Solution :

t /2,df = 1.984

Margin of error = E = t/2,df * (s /n)

= 1.984 * (120 / 100)

Margin of error = E = 23.8

The 95% confidence interval estimate of the population mean is,

- E < < + E

800 - 23.8 < < 800 + 23.8

776.2 < < 823.8

($776.2 , 823.8)

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