What is the probability all 6 faces of a fair die turn up at least twice in 20 rolls.
Answer)
As there are fixed number of trials and probability of each and every trial is same and independent of each other
Here we need to use the binomial formula
P(r) = ncr*(p^r)*(1-p)^n-r
Ncr = n!/(r!*(n-r)!)
N! = N*n-1*n-2*n-3*n-4*n-5........till 1
For example 5! = 5*4*3*2*1
Special case is 0! = 1
P = probability of single trial = 1/6 = 0.167
N = number of trials = 20
R = desired success = at least 2
We know that sum of all the probabilities is = 1.
So, P(at least 2) = 1 - (p(0) + p(1)) = 0.87037062968
Get Answers For Free
Most questions answered within 1 hours.