A survey of a group of students at a certain college, we call College ABC, asked: "About how many hours do you study in a week?" The mean response of the 400 students is 15.8 hours. Suppose that the study time distribution of the population is known to be normal with a standard deviation of 8.5 hours. Use the survey results to construct a 95% confidence interval for the mean study time at the College ABC. Show your work neatly.
Solution :
Given that,
Sample size = n = 400
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * (8.5 / 400)
= 0.8
At 95% confidence interval estimate of the population mean is,
- E < < + E
15.8 - 0.8 < < 15.8 + 0.8
15.0 < < 16.6
(15.0 , 16.6)
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