Determine the required value of the missing probability to make
the distribution a discrete probability distribution.
x | p(x) |
3 |
0.32 |
4 | ? |
5 | 0.29 |
6 | 0.12 |
We know that for a discrete probability distribution, the total probability is always equal to 1, i.e.,
where P(x) = P(X=x), where x is the mass point of the discrete probability distribution.
Now, let P(4) = P(X=4) = c. So we must have
P(3) + P(4) + P(5) + P(6) = 1
or, 0.32 + c + 0.29 + 0.12 = 1
or, c + 0.73 = 1
or, c = 1 - 0.73
or c = 0.27
P(4) = P(X=4) = 0.27 , which is the required answer.
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