Question

	Childhood			Adult
	Deviance			Depression
	(X)			(Y)
Mean =	5.33		Mean =	4.15
SD =	2.15		SD =	1.79
		r = 0.811

If a person has a Childhood Deviance Score of 4, what is their predicted Adult Depression Score?

If a person has a Childhood Deviance Score of 7, what is their predicted Adult Depression Score?

If a person has an Adult Depression Score of 2, what was their predicted Childhood Deviance Score?

If a person has an Adult Depression Score of 6, what was their predicted Childhood Deviance Score?

Answer 1

Correlation, r = 0.811

x̅ = 5.33

y̅ = 4.15

sx = 2.15

sy = 1.79

Slope, b = r*sy/sx = 0.811*1.79/2.15 = 0.675205

Intercept, a = y̅ - b* x̅ = 4.15 - (0.6752)*5.33 = 0.551159

Regression equation :

ŷ = 0.5512 + (0.6752) x

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1. Predicted value of y at x = 4

ŷ = 0.5512 + (0.6752) * 4 = 3.252

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2. Predicted value of y at x = 7

ŷ = 0.5512 + (0.6752) * 7 = 5.2776

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3. When ŷ = 2, then x =

x = (2 - 0.5512)/0.6752 = 2.1458

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4. When ŷ = 6, then x =

x = (6 - 0.5512)/0.6752 = 8.0699