A yogurt company claims that their 8-oz low fat yogurt contains an average, at most, 150 calories per cup. A random sample of 10 cups produced a mean of 152.7 calories with a standard deviation of 7.38 calories. Test the yogurt company's claim with a 2.5% level of significance.
Solution :
= 150
=152.7
S =7.38
n = 10
This is the left tailed test .
The null and alternative hypothesis is ,
H0 : = 150
Ha : < 150
Test statistic = t
= ( - ) / S / n
= (152.7-150) / 7.38 / 10
= 1.157
Test statistic = t = 1.157
P-value =0.8615
= 0.025
P-value >
0.8615 > 0.025
Fail to reject the null hypothesis .
There is insufficient evidence to suggest that
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