Suppose data set X has mean μ = 400 and standard deviation σ =
50. If a random sample
of size 100 is collected and ̄x is the sample mean, compute P(395 ≤
x ̄ ≤ 410).
Solution :
Given that,
mean = = 400
standard deviation = = 50
n = 100
= 400
= / n = 50 100 = 5
P( 395 ≤ ≤ 410 )
P (395- 400 / 5 ) ≤ ( - / ) ≤ ( 410 - 400 / 5)
P ( - 5 / 5 ≤ z ≤ 10 / 5 )
P (-1 ≤ z ≤ 2 )
P ( z ≤ 2 ) - P ( z ≤ -1 )
Using z table
= 0.9772 - 0.1587
= 0.8185
Probability = 0.8185
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