The production employees at a garment factory have been surveyed several times to determine the proportion of employees who are opposed to a union. The estimates of this proportion ranged from 60% to 80%. The management agrees that they want a 90% confidence interval estimate with a halfwidth of 2%. What sample size should they use?
Solution :
Point estimate = = (Lower confidence interval + Upper confidence interval ) / 2
Point estimate = = (0.60 + 0.80) / 2
Point estimate = = 0.70
1 - = 1 - 0.70 = 0.30
margin of error = E = 0.02
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
/2
= 0.05
Z/2
= Z0.05 = 1.645
sample size = n = (Z / 2 / E )2 * * (1 - )
= (1.645 / 0.02)2 * 0.70 *0.30
= 1420.66
sample size = n = 1421
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