Question

here ∑x⁢w is obtained by multiplying each data value by its weight and then adding the products. Suppose an instructor gives two ex**ms and a final, assigning the final a weight twice that of each of the other ex*ms. Find the weighted mean for a student who scores 61 and 75 on the first two ex*ms and 87 on the final

Enter the exact answer.

Answer 1

An instructor gives two tests and a final, assigning the final a weight twice that of each of the other texts.

Now, if the weightage of the first two tests is x, then the weight of the final must be 2x.

Now, the total weightage must be 1.

So, we can say that

Thus, we can conclude that the weightage on the two tests is 0.25 each, and on the final, is 0.50.

Now, a student scores 61 and 75 in the first two tests and 87 on the final.

Here, involving the weightages on the tests, the exact score becomes

The combined exact score is 77.5.