Suppose that you and two friends go to a restaurant, which last month filled approximately 88.3 % of the orders correctly.
What are the mean and standard deviation of the binomial distribution? Interpret these values.
The mean is_____
The standard deviation is_____
Interpret the mean and standard deviation
On average, ____ orders are correctly filled, while there is an approximate variation of _____ from the ____(maximum, minimun, or average) number of orders_____(taken, correctly filled, or incorrectly filled)
Round to four decimal places as needed for each question.
Sample size (n) = 3
p = P(Filled orders correctly) = 88.3% = 0.883
Mean of the binomial distribution is, n*p
Hence, Mean = 3*0.883 = 2.649
The standard deviation of the binomial distribution is,
Standard deviation = 0.5567
Variance = (standard deviation)^2 = 0.3099
The interpretation of mean and standard deviation:
On average, 2.694 orders are correctly filled, while there is an approximate variation of 0.5567 from the average number of orders correctly filled.
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