The proportion of drivers who use seat belts depends on things like age, gender, and ethnicity. As part of a broader study, investigators observed a random sample of 121 female Hispanic drivers in Boston. Suppose that in fact 66% of all female Hispanic drivers in the Boston area wear seat belts. In repeated samples, the sample proportion p^ would follow approximately a Normal distribution.
What is the standard deviation of p^ ? (Enter your answer rounded to four decimal places.)
standard deviation:
Solution
Given that,
p = 0.66
1 - p = 1-0.66=0.34
n = 121
= p =0.66
standard deviation= = [p ( 1 - p ) / n] = [(0.66*0.34) / 121 ] = 0.0431
standard deviation= =0.0431
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