To test the hypothesis that the population standard deviation sigma=4.9, a sample size n=25 yields a sample standard deviation 3.437. Calculate the P-value and choose the correct conclusion.
Your answer: |
|
---|---|
The P-value 0.018 is not significant and so does not strongly suggest that sigma<4.9. |
|
The P-value 0.018 is significant and so strongly suggests that sigma<4.9. |
|
The P-value 0.028 is not significant and so does not strongly suggest that sigma<4.9. |
|
The P-value 0.028 is significant and so strongly suggests that sigma<4.9. |
|
The P-value 0.218 is not significant and so does not strongly suggest that sigma<4.9. |
|
The P-value 0.218 is significant and so strongly suggests that sigma<4.9. |
|
The P-value 0.374 is not significant and so does not strongly suggest that sigma<4.9. |
|
The P-value 0.374 is significant and so strongly suggests that sigma<4.9. |
|
The P-value 0.025 is not significant and so does not strongly suggest that sigma<4.9. |
|
The P-value 0.025 is significant and so strongly suggests that sigma<4.9. |
The P-value 0.018 is significant and so strongly suggests that sigma<4.9.
Solution:
From given information, we have
The test statistic formula is given as below:
Chi-square = (n – 1)*S^2/ σ2
From given data, we have
n = 25
S = 3.437
σ = 4.9
Chi-square =(25 - 1)*3.437^2 / 4.9^2
Chi-square = 11.8080
We assume
Level of significance = α = 0.05
df = n – 1
df = 25 - 1 = 24
P-value = 0.0180
(by using Chi square table or excel)
P-value < α = 0.05
So, we reject the null hypothesis
Get Answers For Free
Most questions answered within 1 hours.