Question

1. Here are the daily average body temperatures (in degrees Fahrenheit) for 20 healthy adults:

98.74, 98.83, 96.80, 98.12, 97.89, 98.09, 97.87, 97.42, 97.30, 97.84, 100.27, 97.90, 99.64, 97.88, 98.54, 98.33, 97.87, 97.48, 98.92, 98.33

Do these data give evidence that the mean body temperature for all healthy adults is not equal to the traditional 98.6 degrees? State the hypotheses, find a P-value, and write a summary of your results. Show your work.

Answer 1

Solution:

Null hypothesis H0: mean = 98.6

Alternate hypothesis Ha: mean is not equal to 98.6

Sample mean = 1964.06/20 = 98.203

Sample standard deviation = Sqrt(summation(Xi-mean)^2/(n-1)) = 0.80

Test stat = (98.203-98.6)/0.80/Sqrt(20)= -2.21

From t table we found p- value at df = 19 and this is two tailed test

So p-value = 0.04

At alpha=0.05, we can reject the null hypothesis as p-value is less than alpha value (0.04<0.05).

And we have significance evidence to support the claim that the mean body temperature for all healthy adults is not equal to the traditional 98.6 degree.