Find the probability that less than 40% of a random sample of 200 people will be blood type O+ if the population proportion is 39%
Enter only the probability.
Solution
Given that,
p = 0.39
1 - p = 1 - 0.39 = 0.61
n = 200
= p = 0.39
= [p ( 1 - p ) / n] = [(0.39 * 0.61) / 200] = 0.0345
P( < 0.40)
= P[( - ) / < (0.40 - 0.39) / 0.0345 ]
= P(z < 0.29)
Using z table,
= 0.6141
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