Suppose 44% of the children in a school are girls. If a sample of 545 children is selected, what is the probability that the sample proportion of girls will be less than 43% ? Round your answer to four decimal places.
Solution
Given that,
p = 44% = 0.44
1 - p = 1 - 0.44 = 0.56
n = 545
= p = 0.44
= [p ( 1 - p ) / n] = [(0.44 * 0.56) / 545 ] = 0.0213
P( < 0.43 )
= P[( - ) / < ( 0.43 - 0.44 ) / 0.0213 ]
= P(z < -0.47 )
Using z table
= 0.3192
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