An experiment has been conducted for four treatments with seven blocks. Complete the following analysis of variance table. (Round your values for mean squares and F to two decimal places, and your p-value to three decimal places.)
Source of Variation |
Sum of Squares |
Degrees of Freedom |
Mean Square |
F | p-value |
---|---|---|---|---|---|
Treatments | 900 | ||||
Blocks | 200 | ||||
Error | |||||
Total | 1,600 |
Use α = 0.05 to test for any significant differences.
State the null and alternative hypotheses.
H0: At least two of the population means are
equal.
Ha: At least two of the population means are
different.H0: Not all the population means are
equal.
Ha: μ1 =
μ2 = μ3 =
μ4 H0:
μ1 ≠ μ2 ≠
μ3 ≠ μ4
Ha: μ1 =
μ2 = μ3 =
μ4H0:
μ1 = μ2 =
μ3 = μ4
Ha: Not all the population means are
equal.H0: μ1 =
μ2 = μ3 =
μ4
Ha: μ1 ≠
μ2 ≠ μ3 ≠
μ4
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Reject H0. There is sufficient evidence to conclude that the means of the four treatments are not all equal.Reject H0. There is not sufficient evidence to conclude that the means of the four treatments are not all equal. Do not reject H0. There is not sufficient evidence to conclude that the means of the four treatments are not all equal.Do not reject H0. There is sufficient evidence to conclude that the means of the four treatments are not all equal.
>> The analysis of variance table:
Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F Statistic | p value |
Treatments | 900 | 3 | 300 | 9.00 | 0.001 |
Blocks | 200 | 6 | 33.33 | ||
Error | 500 | 18 | 27.78 | ||
Total | 1600 | 27 |
>> The null and alternative hypotheses:
H0: μ1 = μ2 = μ3 = μ4
Ha: Not all the population means are equal.
>> The value of the test statistic = 9.00
>> The p-value = 0.001
>> Conclusion: Reject H0. There is sufficient evidence to conclude that the means of the four treatments are not all equal.
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