COMBINATION
Solve each of the following problems. (Show your work.)
women. In how many ways may these vacancies be filled
a). with any two of the nominees?
b). with any two of the women?
c). with one of the men and one of the women?
a). at least two ladies are included? b). at most two ladies are included?
a). are no further restrictions? b). must be at least 1 girl?
c). must be a particular boy chosen? d). must be more boys than girls?
e). must be at most 2 girls only?
a). with the same color b). with different colors
c). 1 red, 1 white d). red or white
a). how many different five-card hands are possible?
b). in how many hands are all five cards the same color?
c). in how many hands are all five cards the same suit?
d). four face cards and one that is not a face card?
e). three queens and two that are not queens?
f). full house (three of a kind, two of a different kind)?
g). royal flush (10, J, Q, K and ace of the same suit)?
h). at least one heart?
i). at least one ace?
j). at most two spades?
season with 5 wins, 4 losses, and 1 tie?
steak, and 2 order lobster?
a). In how many ways may a student mark the test, if each question is answered?
b). In how many ways may a student mark the test, if 7 questions are marked correctly and
3 incorrectly?
c). In how many ways may a student mark the test, if 5 questions are marked correctly
and 5 incorrectly?
ls, 5 white balls and 5 blue balls if each selection consists of 4 balls of each color.Find the number of ways of selecting 12 balls from 6 red balls, 5 white balls and 5 blue balls if each selection consists of 4 balls of each color.
Number of ways of selecting 4 red balls, 4 white balls and 4 blue balls is
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Since there are 4 men and 6 women so total number of nominees are 4+6 = 10.
(a)
Number of ways of selecting 2 nominees are
(b)
Number of ways of selecting 2 women out of 6 is
(c)
Number of ways of selecting 1 man and 1 woman out of 6 is
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