you are the operations manager for an airline and you are considering a higher fare level foer passengers in aisle seats. how many randomly selected passengers must you survey? assume that a prior survey suggest that about 43% of air passengers prefer aisle seat. assume that you want to be 87% confident that the sample percentage is within 2.8 percentage points of the tru population percentage.
Solution:
Given,
p = 43% = 0.43
1- p = 1 - 0.43 = 0.57
E = 2.8% = 0.028
c = 87% = 0.87
Now,
= 1 - c = 1 - 0.87 = 0.13
/2 = 0.065
= 1.514 (using z table)
The sample size for estimating the proportion is given by
n =
= (1.514)2 * 0.43 * 0.57 / (0.0282)
= 716.60
= 717 ..(round to the next whole number)
Answer : Required Sample size is n = 717
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