The 10 letters in "statistics' are each written on equal-sized disks and placed in a bag. A disk is randomly drawn and the letter is noted. Compute the following probabilities:
a. P( i or t) answer from book 5/10
b. P( a vowel or letter s) answer from book 6/10
c. P( a letter in "algrebra" or " geometry") answer from book 4/10
d. P(a letter in "probability" or "certainty") answer from book 7/10
Please show me how the book got those answers.
a) total number of letters =10
total number of i =2
total number of t =3
hence total number of i or t =2+3 =5
P( i or t) =favourable outcome/total outcome=5/10
b)
number of vowels =number of i's +number of a's =2+1=3
number of s =3
hence P( a vowel or letter s) =(3+3)/10=6/10
c) common letters between "statistics' and "algrebra" or " geometry" are a and t
total number of a=1
total number of t =3
hence P( a letter in "algrebra" or " geometry") =(1+3)/10=4/10
d) common letters between "statistics' and "probability" or "certainty" are a ; i ;c and t
total number of a=1
total number of t =3
total number of c=1
total number of i =2
hence P(a letter in "probability" or "certainty") =(1+3+1+2)/10=7/10
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