Question

6. Normal cytokine count for non disease carrying patients are found to be distributed normally with...

6. Normal cytokine count for non disease carrying patients are found to be distributed normally with a mean and standard deviation of 55 and 10 respectively. If a patient is found to have a cytokine count below two standard deviations from the mean (<35) they are declared disease positive.1

Unbeknownst to anyone (except you), disease carrying patients have a normally distributed cytokine count with mean and standard deviation of 20 and 10 respectively

.i) What proportion of disease carrying patients who are tested will not be declared disease positive? (find the false negative rate).

ii) What proportion of non disease carrying patients tested will falsely be declared disease positive? (find the false positive rate)

Homework Answers

Answer #1

i)

Proportion of disease carrying patients who are tested but will not be declared disease positive = P(cytokine count for disease carrying patient is greater than 35)

= P{Z > (35 - 20)/10} = P(Z > 1.5) = 0.0668

The false negative rate = 0.0668 = 6.68%

ii) Proportion of non disease carrying patients tested but falsely declared as disease positive = P(cytokine count for non disease carrying patient is smaller than 35)

= P{Z < (35 - 55)/10}

= P(Z < -2)

= 0.0228 = 2.28%

The false positive rate = 2.28%

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A psychologist finds that the intelligence quotients of a group of patients are normally distributed, with...
A psychologist finds that the intelligence quotients of a group of patients are normally distributed, with a mean of 104 and a standard deviation of 16. Find the percent of the patients with the following IQs. (a) above 116 % (b) between 92 and 122
#6 a survey found that women’s heights are normally distributed with mean 62.2 in. and standard...
#6 a survey found that women’s heights are normally distributed with mean 62.2 in. and standard deviation 2.7 in, the survey also found that men’s heights are normally distributed with a mean 68.7in. and standard deviation 2.8. a. most of the live characters at an amusement park have height requirements with a minimum of 4ft. 8in. and a maximum of 6ft. 3in. find the percentage of women meeting the height requirement, b finds the percentage of men meeting the height...
a survey found that women’s heights are normally distributed with a mean of 63.4 in and...
a survey found that women’s heights are normally distributed with a mean of 63.4 in and a standard deviation of 3.3 the survey also found that men’s heights are normally distributed with a mean of 67.3 and a standard deviation of 3.5 in. most of the live characters employed at the amusement park have a height requirement of a minimum of 56 and a maximum of 63 inches. find the percentage of men meeting that height requirement. what does the...
Q1 Part A.) A survey found that​ women's heights are normally distributed with mean 63.1 in....
Q1 Part A.) A survey found that​ women's heights are normally distributed with mean 63.1 in. and standard deviation 3.5 in. The survey also found that​ men's heights are normally distributed with mean 68.6 in. and standard deviation 3.2 in. Consider an executive jet that seats six with a doorway height of 55.8 in. Complete parts​ (a) through​ (c) below. a. What percentage of adult men can fit through the door without​ bending? The percentage of men who can fit...
A survey found that women's heights are normally distributed with mean 63.4 in and standard deviation...
A survey found that women's heights are normally distributed with mean 63.4 in and standard deviation 3.3 in. The survey also found that men's heights are normally distributed with mean 68.3 in. and standard deviation 3.6. Most of the live charcters employed at an amusement park have height requirements of a minimum of 56 in and a maximum of 62 in . Find the percentage of men meeting the height requirement. What does the result suggest about the genders of...
Suppose that women’s hourly earnings are distributed non-normally with mean $20 and standard deviation $10. What...
Suppose that women’s hourly earnings are distributed non-normally with mean $20 and standard deviation $10. What is the sampling distribution of the mean in SRS for n=100?
A study investigated ways to prevent staph infections in surgery patients. In a first step, the...
A study investigated ways to prevent staph infections in surgery patients. In a first step, the researchers examined the nasal secretions of a random sample of 6771 patients admitted to various hospitals for surgery. They found that 1251 of these patients tested positive for Staphylococcus aureus, a bacterium responsible for most staph infections. Let the mean of the sampling distribution be p=0.19. a) What does p stand for in this case (in words)? What is the sample in this case?...
Assume that the time spent by all patients who visit the dentist is normally distributed. A...
Assume that the time spent by all patients who visit the dentist is normally distributed. A random sample of 25 patients who visited a dentist spent an average of 55 minutes on a visit with a standard deviation of 20 minutes. Find the population mean interval with a 90% confidence level. Round the answer to the nearest whole number.
A survey found that​ women's heights are normally distributed with mean 63.763.7 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 63.763.7 in. and standard deviation 3.43.4 in. The survey also found that​ men's heights are normally distributed with mean 69.169.1 in. and standard deviation 3.63.6 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 5656 in. and a maximum of 6464 in. Complete parts​ (a) and​ (b) below. a. Find the percentage of men meeting the height requirement. What does...
3.Assume that the readings at freezing on a batch of thermometers are normally distributed with a...
3.Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than 1.865°C. P(Z>1.865)=P(Z>1.865)= (Round to four decimal places) 4.Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT