The manager of Toy World knows that the probability an
electronic game will be returned to the store is 0.22. If 54 games
are sold in a given week, determine the probabilities of the
following events. (Round your answers to four decimal
places.)
(a) No more than 12 games will be returned.
(b) At least 8 games will be returned.
(c) More than 5 games but fewer than 14 games will be returned.
n = 54
p = 0.22
np = 54 * 0.22 = 11.88
n(1 - p) = 54 * 0.78 = 42.12
As np > 5 and n(1 - p) > 5, so we can use normal approximation to the binomial distribution.
= np = 54 * 0.22 = 11.88
= sqrt(54 * 0.22 * 0.78) = 3.044
a) P(X < 12)
= P(X < 12.5)
= P((X - )/< (12.5 - )/)
= P(Z < (12.5 - 11.88)/3.044)
= P(Z < 0.20)
= 0.5793
b) P(X > 8)
= P(X > 7.5)
= P((X - )/< (7.5 - )/)
= P(Z < (7.5 - 11.88)/3.044)
= P(Z < -1.44)
= 0.0749
c) P(5 < X < 14)
= P(6 < X < 13)
= P(5.5 < X < 13.5)
= P((5.5 - )/< (X - )/< (13.5 - )/)
= P((5.5 - 11.88)/3.044 < Z < (13.5 - 11.88)/3.044)
= P(-2.10 < Z < 0.53)
= P(Z < 0.53) - P(Z < -2.10)
= 0.7019 - 0.0179
= 0.684
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