Fill in the values in the table below to give a legitimate probability distribution for the discrete random variable , whose possible values are -5, -4,2,4,and 6 .
Value x of X
-5,-4,2,4, 6
(PX=x)
____
____
0.22
0.27
0.15
We are given the values of x, -5, -4, 2, 4, 6
X | P(X =x) |
-5 | ? |
-4 | ? |
2 | 0.22 |
4 | 0.27 |
6 | 0.15 |
We need to find P(X = -5) and P(X = -4)
Suppose, P(X = -5) = P(X = -4) = a
P(X = -5) + P(X = -4) + P(X = 2) + P(X =4) + P(X =6) = 1
a + a + 0.22 +0.27 0.15 = 1
2a + 0.64 = 1
2a = 1 - 0.64
2a = 0.36
a = 0.18
That is, P(X = -5) = 0.18
And P(X = -4) = 0.18
Hence, the table should be as follows:
X | P(X =x) |
-5 | 0.18 |
-4 | 0.18 |
2 | 0.22 |
4 | 0.27 |
6 | 0.15 |
Get Answers For Free
Most questions answered within 1 hours.