Question
Pages Pages 2698 2028 Mean 2408.8 2474 Standard Error 96.2684672 2395 Median 2387 2372 Mode #N/A...
| Pages | Pages | ||
| 2698 | |||
| 2028 | Mean | 2408.8 | |
| 2474 | Standard Error | 96.2684672 | |
| 2395 | Median | 2387 | |
| 2372 | Mode | #N/A | |
| 2475 | Standard Deviation | 304.4276232 | |
| 1927 | Sample Variance | 92676.17778 | |
| 3006 | Kurtosis | 0.976147469 | |
| 2334 | Skewness | 0.345521688 | |
| 2379 | Range | 1079 | |
| Minimum | 1927 | ||
| Maximum | 3006 | ||
| Sum | 24088 | ||
| Count | 10 | ||
| Confidence Level(95.0%) | 217.7744026 | ||
Please answer these questions by using the information above.
- What is the point estimate?
- What is the confidence interval (using the information you generated)?
- What is the approximate probability that the true mean number of pages printed by the new ink-jet printer is equal to or less than 2,191?
- Finally, verify your results by manually calculating the mean of the sample. Go on to determine the standard deviation and the standard error of the mean. Then compute a confidence interval based on your manually created numbers. If your interval happens to differ from the one generated by excel, please try to explain why.
Homework Answers
Answer #1
i. Point Estimate = mean = 2408.8
ii. Confidence interval = 2408.8 
217.7744 = (2191.0256 , 2626.5744)
iii. Probability that the true mean number of pages printed by the new ink-jet printer is equal to or less than 2,191:
Manual calculations:
Mean:
Standard deviation:
Standard error:
Confidence interval
Both confidence interval exact same only the difference between decimal places. This occur due to round of decimal places.
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