A call center claims their average call lasts 6 minutes. Let's take a sample of 30 call center agents with a mean of 7.2 minutes and a standard deviation of 1.9 minutes. Can the claim at an alpha of 0.08?
Solution:
Here, we have to use one sample t test for the population mean.
The null and alternative hypotheses are given as below:
H0: µ = 6 versus Ha: µ ≠ 6
This is a two tailed test.
The test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
From given data, we have
µ = 6
Xbar = 7.2
S = 1.9
n = 30
df = n – 1 = 29
α = 0.08
Critical value = - 1.8142 and 1.8142
(by using t-table or excel)
t = (Xbar - µ)/[S/sqrt(n)]
t = (7.2 - 6)/[1.9/sqrt(30)]
t = 3.4593
P-value = 0.0017
(by using t-table)
P-value < α = 0.08
So, we reject the null hypothesis
There is not sufficient evidence to conclude that the average call lasts 6 minutes.
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