Two sample summary hypothesis test. Consider a random sample of 14 M&M'S. Each weighed 2.5, 2.1, 2.7, 2.3, 3.0, 2.4 and 2.7. And the remaining 7 plain M&M'S weighed 08, 0.9, 0.8, 0.7, 0.9, and 0.6.
The hypothesis being tested is:
H0: µ1 = µ2
H1: µ1 ≠ µ2
Group 1 | Group 2 | |
2.529 | 0.783 | mean |
0.298 | 0.117 | std. dev. |
7 | 6 | n |
8 | df | |
1.7452 | difference (Group 1 - Group 2) | |
0.1225 | standard error of difference | |
0 | hypothesized difference | |
14.250 | t | |
5.73E-07 | p-value (two-tailed) |
The p-value is 0.0000.
Since the p-value (0.0000) is less than the significance level (0.05), we can reject the null hypothesis.
Therefore, we can conclude that µ1 ≠ µ2.
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