A data set includes data from student evaluations of courses. The summary statistics are nequals93, x overbarequals4.15, sequals0.59. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.25. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
This is the two tailed test .
The null and alternative hypothesis is
H0 : = 4.25
Ha : 4.25
Test statistic = t
= ( - ) / s / n
= (4.15 - 4.25) / 0.59 / 93
Test statistic = -1.635
df = 92
P-value = 0.1056
= 0.01
P-value >
Fail to reject the null hypothesis .
There is not sufficient evidence to conclude that the population of student course
evaluations has a mean equal to 4.25.
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