Question

A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...

A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 22 hours after taking the drug are shown in the table below. Using this data, find the 90%90% confidence interval for the true difference in blood pressure for each patient after taking the new drug. Assume that the blood pressures are normally distributed for the population of patients both before and after taking the new drug.

Patient 1 2 3 4 5 6 7 8 9
Blood pressure (before) 172172 196196 197197 191191 181181 193193 205205 189189 157157
Blood pressure (after) 148148 170170 171171 169169 161161 181181 199199 177177 150150

Copy Data

Step 1 of 4:

Find the point estimate for the population mean of the paired differences. Let x1x1 be the blood pressure before taking the new drug andx2x2 be the blood pressure after taking the new drug and use the formula d=x2−x1d=x2−x1 to calculate the paired differences. Round your answer to one decimal place.

Step 2 of 4:

Calculate the sample standard deviation of the paired differences. Round your answer to six decimal places.

step 3 of 4

Calculate the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.

Step 4 of 4:

Construct the 90%90% confidence interval. Round your answers to one decimal place.

Homework Answers

Answer #1

using excel>addin>phstat>confidence interval

we have

Confidence Interval Estimate for the Mean
Data
Sample Standard Deviation 8.027729719
Sample Mean -17.2222222
Sample Size 9
Confidence Level 90%
Intermediate Calculations
Standard Error of the Mean 2.675909906
Degrees of Freedom 8
t Value 1.8595
Margin of Error 4.975983
Confidence Interval
Interval Lower Limit -22.20
Interval Upper Limit -12.25

Step 1 of 4:  the point estimate for the population mean of the paired differences is -17.2

Step 2 of 4: the sample standard deviation of the paired differences is 8.027730

step 3 of 4 the margin of error to be used in constructing the confidence interval is 4.975983


Step 4 of 4:the 90% confidence interval is (-22.2 ,-12.3)

'

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Using this data, find the 90% confidence interval for the true difference in blood pressure for each patient after taking the new drug. Assume that the blood pressures are normally distributed for the population of patients both before and...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Using this data, find the 95% confidence interval for the true difference in blood pressure for each patient after taking the new drug. Assume that the blood pressures are normally distributed for the population of patients both before and...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Using this data, find the 99% confidence interval for the true difference in blood pressure for each patient after taking the new drug. Assume that the blood pressures are normally distributed for the population of patients both before and...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 22 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug)d=(blood pressure before taking new drug)−(blood pressure after taking new drug). Use a significance level of α=0.01α=0.01 for the...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug)d=(blood pressure before taking new drug)−(blood pressure after taking new drug). Use a significance level of α=0.01 for the...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug) d = (blood pressure before taking new drug) − (blood pressure after taking new drug) . Use a...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug). Use a significance level of α=0.05 for the test. Assume that the systolic blood pressure levels are normally...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 2 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug) . Use a significance level of α=0.05 for the test. Assume that the systolic blood pressure levels are...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure...
A pharmaceutical company claims that its new drug reduces systolic blood pressure. The systolic blood pressure (in millimeters of mercury) for nine patients before taking the new drug and 22 hours after taking the drug are shown in the table below. Is there enough evidence to support the company's claim? Let d=(blood pressure before taking new drug)−(blood pressure after taking new drug). Use a significance level of α=0.01 for the test. Assume that the systolic blood pressure levels are normally...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported...
A sleep disorder specialist wants to test the effectiveness of a new drug that is reported to increase the number of hours of sleep patients get during the night. To do so, the specialist randomly selects nine patients and records the number of hours of sleep each gets with and without the new drug. The results of the two-night study are listed below. Using this data, find the 90% confidence interval for the true difference in hours of sleep between...