Question

The amount of time spent by a statistical consultant with a client at their first meeting is a random variable having a normal distribution with a mean value of 60 minutes and a standard deviation of 10 minutes.

What is the probability that more than 45 minutes is spent at the first meeting? Round your answer to three decimal places.

Answer 1

Solution :

Given that ,

mean = = 60

standard deviation = = 10

P(X > 45) = 1 - P(x < 45)

= 1 - P((x - ) / < (45 - 60) / 10)

= 1 - P(z < -1.5)   Using standard normal table,

= 1 - 0.0668   

= 0.9332

P(x > 45) = 0.933

Probability = 0.933