Question

to determine how well the film wonder woman 1984, will do in western canada, market reseaxhers plan to observe random samples in calgary edmonton winnipeg and vancouver measuring whether people intend to se the film in opening day in the first week, at some time later or not at all. use a single test see if any of the proportions are different between cities. if the test stat is 16.993. what is the p-value range?

Answer 1

Solution:

For the given scenario, we need to use Chi-square test for the independence between two categorical variables.

Test statistic = Chi-square = 16.993

We are given

Number of rows = r = 4

(Calgary, Edmonton, Winnipeg, Vancouver)

Number of columns = c = 3

(First week, at some time later, not at all)

Degrees of freedom = df = (r – 1)*(c – 1) = 3*2 = 6

Degrees of freedom = 6

So, the P-value by using Chi-square table or excel is given as below:

P-value = 0.009309

P-value is lies between 0 and 0.01.

P-value range is given as below:

0 < P-value < 0.01