Question

According to a survey, 16% of U.S. adults with online services currently read e-books. Assume that this percentage is true for the current population of U.S. adults with online services. Find to 4 decimal places the probability that in a random sample of 600 U.S. adults with online services, the number who read e-books is

a. exactly 86.

Probability = Entry field with incorrect answer

b. at most 119.

Probability = Entry field with correct answer

c. 71 to 97.

Probability =

Answer 1

This probabilities are solved by using R

Output :

Summary:

  Given
n=600 , p=0.16
This can be solved by using binomial distribution .
1)exactly 16
Answer : P= 0.0000

2)at most 119 i.e. P( x <= 119)
Answer : P= 0.9946

3)between 71 to 97 that is P( 71 < X < 97) =P( X<= 96)- p(X < =71)
Answer : P= 0.5248