Assume that a sample is used to estimate a population proportion
p. Find the margin of error M.E. that corresponds
to a sample of size 272 with 26.1% successes at a confidence level
of 99.5%.
M.E. =
Solution :
Given that,
Point estimate = sample proportion = = 0.261
1 - = 1 - 0.261 = 0.739
Z/2 = Z0.0025 = 2.807
Margin of error = E = Z / 2 * (( * (1 - )) / n)
M.E. = 2.807 (((0.261 * 0.739) / 272)
M.E. = 0.075
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