Question

suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. use a 0.10 signigicance level to test that claim. Identify the P-value for this hypotheisi test.

Answer 1

Given : Sample size=n=100

Estimate of the sample proportion=

Hypothesized value=p0=0.26

Significance level==0.10

The null and alternative hypothesis is ,

The test is two-tailed test.

The test statistic is ,

The p-value is ,

p-value=

; From standard normal distribution table

Decision : Here , p-value=0.6456>0.10

Therefore , fail to reject the null hypothesis.

Conclusion : There is sufficient evidence to support the claim that the percentage of blue candies is equal to 26%.