4.
Group Statistics |
|||||
protestant |
N |
Mean |
Std. Deviation |
Std. Error Mean |
|
HIGHEST YEAR OF SCHOOL COMPLETED |
.00 |
1260 |
13.32 |
3.219 |
.091 |
1.00 |
745 |
13.62 |
2.810 |
.103 |
Using this information
a) Conduct an independent samples t-test for these means
b) Find the effect size
A)
Answer)
As the sample sizes are extremely large, we can use standard normal z table to estimate the answer.
Null hypothesis Ho : u1 = u2
Alternate hypothesis Ha : u1 not equal to u2
Test statistics z = (x1-x2)/standard error
Standard error = √{(s1^2/n1)+(s2^2/n2)}
X1 = 13.32, X2 = 13.62
N1 = 1260, N2 = 745
S1 = 3.219, S2 = 2.81
After substitution,=
Z = -2.19
From z table, P(z<-2.19) = 0.0143
As the test is two tailed,
P-value is = 2*0.0143 = 0.0286
As the obtained, p-value is < 0.05.
We reject the null hypothesis Ho.
B)
Effect size = (x1-x2)/pooled s.d
Pooled s.d =
Sp = √{(n1-1)*s1^2 + (n2-1)*s2^2 }/√{n1+n2-2}
After substitution,
Effect size = −0.0976104890 = -0.0976
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