An urn contains 8 white balls and 4 red balls. The experiment consists of drawing 2 balls at random from the urn without replacement.
a) What is the probability that both will be the same color?
b) Same question for part A, but with replacement.
a) Probability that both the balls drawn are of same color is computed here as:
= Probability that both balls drawn are white + Probability that both drawn balls are red
Therefore 0.5152 is the required probability here.
b) Given that we are drawing the balls with replacement here, therefore the probability of drawing a white ball remains same in both draws, similarly probability of getting a red ball also remains the same. The probability thus is computed here as:
Therefore 5/9 is the required probability here.
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