You are trying to decide whether to play a carnival game that costs $1.50 to play. The game consists of rolling 3 fair dice. If the number 1 comes up at all, you get your money back, and get $1 for each time it comes up. So for example if it came up twice, your profit would be $2. The table below gives the probability of each value for the random variable X, where:
X = profit from playing the carnival game (in $).
What happened? |
X = profit in $ |
P(X) |
Did not roll any 1's |
-$1.50 |
0.5787 |
Rolled a single 1 |
$1.00 |
0.3472 |
Rolled two 1's |
$2.00 |
0.0694 |
Rolled three 1's |
$3.00 |
0.0046 |
a. Find the expected value of the random variable X. Keep in mind it may be negative. Round your answer to 2 decimal places.
b. If you played the carnival game 1000 times, how much money would you expect to lose? Round your answer to the nearest whole number.
Interpret your findings. Select your answer from one of the following options.
Question (a)
Expected value = Xi * P(Xi)
So expected value of the random variable X here = (-1.5) * 0.5787 + 1.00 * 0.3472 + 2.00 * 0.0694 + 3.00 * 0.0046
= -0.8681 + 0.3472 + 0.1388 + 0.0138
= -0.36825
= -$0.37
Question (b)
If you played the carnival game 1000 times, how much money would you expect to lose
Money you expect to lose = 1000 * (-0.36825)
= -368.25
= -$368
So you expect to lose $368
Question (c)
Thoguh you play a large number of games, at the end you will always loose money because the expected value of the game here is negative
The expected value is small but negative, so in the long term, if you play the game a large number of times, even though you will win some, you will have less money than when you started.
So Answer is Option C
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