A ski gondola carries skiers to the top of a mountain. Assume
that weights of skiers are normally distributed with a mean of 183
lb and a standard deviation of 37 lb. The gondola has a stated
capacity of 25 passengers, and the gondola is rated for a load
limit of 3500 lb. Complete parts (a) through (d) below.
a. Given that the gondola is rated for a load limit of 3500 lb,
what is the maximum mean weight of the passengers if the gondola is
filled to the stated capacity of 25 passengers?
The maximum mean weight is 140 lb.
(Type an integer or a decimal. Do not round.)
b. If the gondola is filled with 25 randomly selected skiers, what
is the probability that their mean weight exceeds the value from
part (a)?
The probability is 11.
(Round to four decimal places as needed.)
c. If the weight assumptions were revised so that the new capacity
became 20 passengers and the gondola is filled with 2020 randomly
selected skiers, what is the probability that their mean weight
exceeds 175 lb, which is the maximum mean weight that does not
cause the total load to exceed 3500 lb?
The probability is nothing.
(Round to four decimal places as needed.)
a) It is given that only 25 passengers can board a gondola at a time and the weight limit for the gondola is 3500 lbs. So, the maximum mean weight would be = 3500 / 25 = 140 lbs.
b) Now, we need to find the probability that the mean weight exceeds 140 lbs.
So, let the random variable denoting mean weight be X.
So, P(X > 140) = 1 - P(X < 140)
= 1 - P(Z < (140-183)/37)
= 1 - P(Z < -1.1621)
= 1 - 0.123
= 0.877
c) P(X > 175) = 1 - P(X< 175)
= 1 - P(Z < (175-183)/37)
= 1 - P(Z < -0.2162)
= 1 - 0.414
= 0.586
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