Application Exercise:
In a fast food company, all male employees with 3 to 5 years of
experience have an average salary of $27900 with a with a standard
deviation of $5090. A random sample of 27 female employees also
having 3 to 5 years of experience had an average salary of $27200.
The company accountant suspects a different in salary practices for
males and females. What can be concluded with an α of
0.10?
a) What is the appropriate test statistic?
---Select--- na z-test one-sample t-test independent-samples t-test
related-samples t-test
b)
Population:
---Select--- fast food company the CEO male employees salary female
employees
Sample:
---Select--- fast food company the CEO male employees salary female
employees
c) Obtain/compute the appropriate values to make a
decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ; test statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
d) If appropriate, compute the CI. If not
appropriate, input "na" for both spaces below.
[ , ]
e) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and select "na" below.
d = ; ---Select--- na trivial effect small
effect medium effect large effect
r2 = ; ---Select--- na trivial
effect small effect medium effect large effect
f) Make an interpretation based on the
results.
The salary of male employees is significantly lower than female employees.
The salary of male employees is significantly higher than female employees.
The salary of male employees did not differ from female employees.
a)
z-test
b)
Population:
male employees
Sample:
female employees
c)
critical value = 1.645; test statistic = -0.715
Decision: Fail to reject H0
d)
[ 25588.75 , 28811.25 ]
e) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and select "na" below.
d = 0.138 ; trivial effect
r2 = ; na
f) Make an interpretation based on the
results.
The salary of male employees did not differ from female employees.
27,200.00 | mean 1 |
5,090.00 | std. dev. |
979.57 | std. error |
27 | n |
0.138 | |
-0.715 | z |
.4749 | p-value (two-tailed) |
25,588.75 | confidence interval 90.% lower |
28,811.25 | confidence interval 90.% upper |
1,611.25 | margin of error |
Get Answers For Free
Most questions answered within 1 hours.