Randomly selected birth records were obtained, and categorized as listed in the table to the right. Use a
0.010
significance level to test the reasonable claim that births occur with equal frequency on the different days of the week. How might the apparent lower frequencies on Saturday and Sunday be explained?
Day nbspDay |
Sun |
Mon |
Tues |
Wed |
Thurs |
Fri |
Sat |
|
---|---|---|---|---|---|---|---|---|
Number of BirthsNumber of Births |
46 |
56 |
61 |
56 |
56 |
56 |
42 |
Determine the null and alternative hypotheses.
Upper H 0H0:
▼
At least one day has a different frequency of births than the other days.
Births occur with all different frequencies on the different days of the week.
Births occur with the same frequency on the different days of the week.
At least two days have a different frequency of births than the other days.
What is the test statistic?
What is p value?
What is null hypothesis?
What is research hypothesis?
Reject or foul to reject null hypothesis because the P value is < or>
null hypothesis :Ho: Births occur with the same frequency on the different days of the week.
Alternate hypothesis: Ha Births occur with all different frequencies on the different days of the week.
2)
applying chi square goodness of fit test: |
relative | observed | Expected | Chi square | ||
category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)2/Ei | |
Sun | 1/7 | 46 | 53.29 | 0.996 | |
Mon | 1/7 | 56 | 53.29 | 0.138 | |
Tue | 1/7 | 61 | 53.29 | 1.117 | |
Wed | 1/7 | 56 | 53.29 | 0.138 | |
Thu | 1/7 | 56 | 53.29 | 0.138 | |
Fri | 1/7 | 56 | 53.29 | 0.138 | |
Sat | 1/7 | 42 | 53.29 | 2.390 | |
total | 1.000 | 373 | 373 | 5.0563 | |
test statistic X2 = | 5.056 |
degree of freedom =categories-1= | 6 |
from excel: p value = | chidist(5.056,6)= | 0.5366 |
Fail to reject null hypothesis because the P value is > 0.01
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