Question

1. In a survey of 3230 ​adults, 1418 say they have started paying bills online in the last year. Construct a​ 99% confidence interval for the population proportion. Interpret the results. A​ 99% confidence interval for the population proportion is (),() . ​(Round to three decimal places as​ needed.)

Answer 1

Solution :

Favourable cases, X = 1418

Sample size , n = 3230

significance level , = 1-99/100 = 0.01

The sample proportion is computed as follows, based on the sample size N = 3230 and the number of favorable cases X = 1418

Therefore

A​ 99% confidence interval for the population proportion is (0.417),(0.462)