A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=946 and 1x=591 who said "yes." Use a %95% confidence level.
a)
Find the best point estimate of the population proportion p.
b) Identify the value of the margin of error E.
c)Construct the confidence interval.
d)Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
Solution :
n =946
x = 591
= x / n = 591/ 946 = 0.625
1 - = 1 - 0.625 = 0.735
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.960* (((0.625 * 0.375) / 946)
= 0.031
A 95% confidence interval for population proportion p is ,
- E < P < + E
0.625 - 0.031 < p < 0.625 + 0.031
0.594 < p < 0.656
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