Question

Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.68. How many customers should the company survey in order to be 92% confident that the margin of error is 0.21 for the confidence interval of true proportion of customers who click on ads on their smartphones?

Answer #1

Solution :

Given that,

= 0.68

1 - = 1 - 0.68 = 0.32

margin of error = E = 0.21

At 92% confidence level the z is ,

= 1 - 92% = 1 - 0.92 = 0.08

/ 2 = 0.08 / 2 = 0.04

Z_{/2}
= Z_{0.04} = 1.751

sample size = n = (Z_{ / 2} / E )^{2} *
* (1 - )

= (1.751 / 0.21)^{2} * 0.68 * 0.32

= 15.1 = 15

Answer = **15**

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Suppose the manager of a shoe store wants to determine the
current percentage of customers who are males. How many customers
should the manager survey in order to be 95%
confident that the estimated (sample) proportion is within
5 percentage points of the true population
proportion of customers who are males?
Z0.10
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Z0.01
Z0.05
1.282
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Suppose the manager of a shoe store wants to determine the
current percentage of customers who are males. How many customers
should the manager survey in order to be 98% confident that the
estimated (sample) proportion is within 5 percentage points of the
true population proportion of customers who are males? z0.10 z0.05
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the table of values above?

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estimated (sample) proportion is within 5 percentage points of the
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