Question

Student Edition of Statistix 10.0     Apartment Data.xlsx, 5/25/2020, 9:09:26 PM One-Sample T Test Null Hypothesis: μ...

Student Edition of Statistix 10.0     Apartment Data.xlsx, 5/25/2020, 9:09:26 PM

One-Sample T Test

Null Hypothesis: μ = 750

Alternative Hyp: μ ≠ 750

                                                         Lower       Upper

Variable    Mean          SE          T DF         P      95% C.I.    95% C.I.

Size 1405.6      60.156      10.90 74    0.0000      1285.7    1525.5

Cases Included 75    Missing Cases 0

  1. State the null and alternative hypotheses that are being tested with the specified test.

(3 points)

Ho:

Ha:

  1. Identify the test statistic and p-value you will use in this test of hypothesis (2 points)

Test Statistic: ____________           P-value: ___________

  1. What assumption(s) is/are necessary for this analysis to be valid? Make sure you state your answer in the words of the problem (4 points)
  1. Make a conclusion for the test of hypothesis conducted above. You should choose a.

(4 points)

Homework Answers

Answer #1

a)

Null Hypothesis: H0 μ = 750

Alternative Hypothesis Ha: μ ≠ 750 ( 2 tailed)

b)Test Statistic: 10.9

p value = 0.000

c) ASSUMPTIONS

1. Test variable should be normally distributed

2. population sample size should be random sample

3. this Data is measurement data

4 cases of the sample is .independent

5. given that population mean is 750

d) conclusion

p value = 0 < all values of alpha or level of significance  

so Null hypothesis is rejected

Hence there is sufficient evidence to conclude that support the claim that there are different

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Create the printout for testing whether the mean low stock price of all NYSE stocks differs...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs from $35 and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/20/2020, 6:48:59 PM One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                          Lower       Upper Variable     Mean       SE       T    DF        P    95% C.I.   95% C.I. Low        45.120   9.9629   1.02   39   0.3160     24.968     65.272 Cases Included 40    Missing Cases 0 In the words of the problem, give a practical conclusion for this test. Make sure to include your choice of α...
2. Create the printout for testing whether the mean current stock price of all NASDAQ stocks...
2. Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds $22.00 and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/21/2020, 5:30:26 AM One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                                                Lower    Upper Variable Mean       SE        T       DF             P      95% C.I. 95% C.I. Close    39.242   7.5372   0.56      64         0.5755   24.185...
Two-Sample T Tests for B by C C           N          Mean       SD         SE 1   &nb
Two-Sample T Tests for B by C C           N          Mean       SD         SE 1           25         1309.2   344.28   68.857 2           25         1060.6   138.63   27.726 Difference                      248.56   262.44   74.229 T-Tests for Mean Difference Null Hypothesis: difference = 0 Alternative Hyp: difference ≠ 0                                                                         Lower    Upper Method Variances           DF          T             P       95% C.I. 95% C.I. Pooled   Equal    48        3.35      0.0016   99.312 397.81 Satterthwaite       Unequal 31.6      3.35      0.0021   97.282 399.84 Homogeneity of Variances   ...
Student Edition of Statistix 10.0 Apartment Data.xlsx, 5/25/2020, 8:39:12 PM Descriptive Statistics    Rent   Size N  ...
Student Edition of Statistix 10.0 Apartment Data.xlsx, 5/25/2020, 8:39:12 PM Descriptive Statistics    Rent   Size N   75   75 Lo 94% CI   1486.0   1290.7 Mean   1836.5   1405.6 Up 94% CI   2187.0   1520.5 SD   1589.2   520.97 Minimum   795.00   818.00 Median   1400.0   1227.0 Maximum   13322   2914.0 For your Price variable, interpret the standard deviation by giving me a range in which you think “most” of the values (i.e., the x’s) will fall. (Hint: you will need to do some math here) (3 points)...
Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds...
Create the printout for testing whether the mean current stock price of all NASDAQ stocks exceeds $22.00 and attach it here. Answer the following questions regarding this printout: One-Sample T Test Null Hypothesis: μ = 22 Alternative Hyp: μ ≠ 22                                                          Lower       Upper Variable     Mean       SE       T    DF        P    95% C.I.   95% C.I. Close      47.942   8.9817   2.89   64   0.0053     29.998     65.885 Cases Included 65    Missing Cases 0 State the assumption necessary for this printout to be valid. State the null and alternative hypotheses that we would use to determine if the mean current stock price of...
Hypothesis Test - One Proportion Sample Size           400 Successes             106 Proportion       0.26500 Null Hypothesis
Hypothesis Test - One Proportion Sample Size           400 Successes             106 Proportion       0.26500 Null Hypothesis: P = 0.25 Alternative Hyp: P ≠ 0.25 Z (uncorrected)     0.69    P 0.4884 Difference       0.01500 Standard Error   0.02207 Method                     95% Confidence Interval Simple Asymptotic             (0.22175, 0.30825) I used Statistix to create a printout for a 95% confidence interval (and the test below) for the proportion of all college students that have a tattoo. Give a practical interpretation for this interval (4 points)...
Create the printout for testing whether the mean closing price of all NYSE stocks differs from...
Create the printout for testing whether the mean closing price of all NYSE stocks differs from the mean closing price of all NASDAQ stocks and attach it here. Answer the following questions regarding this printout: Student Edition of Statistix 10.0                          4/21/2020, 5:32:15 AM Two-Sample T Tests for Close by Exchange Exchange           N         Mean       SD        SE 0                         40        51.664   73.709   11.654 1                         25        19.368   18.703   3.7406 Difference                    32.296   59.131   15.076 T-Tests for Mean Difference Null Hypothesis:...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs...
Create the printout for testing whether the mean low stock price of all NYSE stocks differs from $35 and attach it here. Answer the following questions regarding this printout: One-Sample T Test Null Hypothesis: μ = 35 Alternative Hyp: μ ≠ 35                                                      Lower      Upper Variable     Mean       SE      T   DF        P   95% C.I.   95% C.I. Low        52.838   9.1892   1.94   39   0.0595     34.251     71.425 Cases Included 40    Missing Cases 0 In the words of the problem, give a practical conclusion for this test. Make sure to include your choice of α in this conclusion b. In the words...
The one sample t-test from a sample of n = 19 observations for the two-sided (two-tailed)...
The one sample t-test from a sample of n = 19 observations for the two-sided (two-tailed) test of H0: μ = 6 H1: μ ≠ 6 Has a t test statistic value = 1.93. You may assume that the original population from which the sample was taken is symmetric and fairly Normal. Computer output for a t test: One-Sample T: Test of mu = 6 vs not = 6 N    Mean    StDev    SE Mean    95% CI            T       P 19 6.200     ...
ttest age == 56 One-sample t test ------------------------------------------------------------------------------ Variable | Obs Mean Std. Err. Std. Dev....
ttest age == 56 One-sample t test ------------------------------------------------------------------------------ Variable | Obs Mean Std. Err. Std. Dev. [95% Conf. Interval] ---------+-------------------------------------------------------------------- age | 2,857 49.15576 .3310101 17.69279 48.50671 49.8048 ------------------------------------------------------------------------------ mean = mean(age) t = -20.6768 Ho: mean = 56 degrees of freedom = 2856 Ha: mean < 56 Ha: mean != 56 Ha: mean > 56 Pr(T < t) = 0.0000 Pr(|T| > |t|) = 0.0000 Pr(T > t) = 1.0000 State the null hypothesis, would you reject or accept...